tag:blogger.com,1999:blog-5895376483669856676.post8934077712047562415..comments2024-01-24T15:06:16.099+05:30Comments on CBSE Papers, Questions, Answers, MCQ ...: CBSE- Class XI - Physics - CH2 - Dimension Analysis #class11Physics #eduvictorsUnknownnoreply@blogger.comBlogger34125tag:blogger.com,1999:blog-5895376483669856676.post-78543270127647695032017-07-16T13:06:31.046+05:302017-07-16T13:06:31.046+05:30WellWellAnonymoushttps://www.blogger.com/profile/11770844812457511789noreply@blogger.comtag:blogger.com,1999:blog-5895376483669856676.post-33189946433557386252017-07-07T20:34:38.464+05:302017-07-07T20:34:38.464+05:30According to question For(force) depends on mass a...According to question For(force) depends on mass and acceleration.F=kma where k is constant. Now solving RHS<br /><br />m= [M^1] and acceleration is distance/time^2. Therefore F = [M][L/T^2] therefore dimensional formula is [MLT^-2]. CHEERS ITS SOLVED.Anonymoushttps://www.blogger.com/profile/14663091107011456245noreply@blogger.comtag:blogger.com,1999:blog-5895376483669856676.post-10797676015558003372017-04-24T15:57:33.711+05:302017-04-24T15:57:33.711+05:30The 22nd questions can be solved in an easier way ...The 22nd questions can be solved in an easier way also. You can express the dimensions in terms of the given one by the 3rd law and take it as a,and c and then just multiply by the value . you will get the answerThe legend gammahttps://www.blogger.com/profile/14870861035270669667noreply@blogger.comtag:blogger.com,1999:blog-5895376483669856676.post-17366971474007510602017-04-20T17:43:05.906+05:302017-04-20T17:43:05.906+05:30plz solve this problem the force acting on the bo...plz solve this problem the force acting on the body depends upon the mass m of the body acceleration find the expression of the body for the forc using the dimensional formulaAnonymoushttps://www.blogger.com/profile/04590516234748010806noreply@blogger.comtag:blogger.com,1999:blog-5895376483669856676.post-19136797216237808042016-09-18T17:06:10.148+05:302016-09-18T17:06:10.148+05:30God bless you. Thanks for these useful data :)God bless you. Thanks for these useful data :)Anonymoushttps://www.blogger.com/profile/00410623327111758400noreply@blogger.comtag:blogger.com,1999:blog-5895376483669856676.post-31452632914174774872016-09-03T04:26:18.314+05:302016-09-03T04:26:18.314+05:30wow helpful hey
wow helpful hey<br />Anonymoushttps://www.blogger.com/profile/01252066840001835382noreply@blogger.comtag:blogger.com,1999:blog-5895376483669856676.post-29728471657228572142016-09-03T04:25:34.992+05:302016-09-03T04:25:34.992+05:30wow helpful hey
wow helpful hey<br />Anonymoushttps://www.blogger.com/profile/01252066840001835382noreply@blogger.comtag:blogger.com,1999:blog-5895376483669856676.post-63427141807657039362016-08-11T10:20:47.940+05:302016-08-11T10:20:47.940+05:30A sphere of radius 50mm and mass 1kg falling verti...A sphere of radius 50mm and mass 1kg falling vertically through air of density 1.2kg / m^3 attains a steady velocity of 11m / s .<br /> If the above equation is applied to its fall what is the value of k in this case? Ans :2 21<br />Gaurav Rizalhttps://www.blogger.com/profile/02167494499823009645noreply@blogger.comtag:blogger.com,1999:blog-5895376483669856676.post-23157657232662167922016-08-11T10:20:11.097+05:302016-08-11T10:20:11.097+05:30A sphere of radius 50mm and mass 1kg falling verti...A sphere of radius 50mm and mass 1kg falling vertically through air of density 1.2kg / m^3 attains a steady velocity of 11m / s .<br /> If the above equation is applied to its fall what is the value of k in this case? Ans :2 21<br />Gaurav Rizalhttps://www.blogger.com/profile/02167494499823009645noreply@blogger.comtag:blogger.com,1999:blog-5895376483669856676.post-32806838513102899972016-08-01T19:25:17.166+05:302016-08-01T19:25:17.166+05:30Me 2Me 2Anonymoushttps://www.blogger.com/profile/10030045071195466526noreply@blogger.comtag:blogger.com,1999:blog-5895376483669856676.post-36139713371311268252016-08-01T19:24:48.924+05:302016-08-01T19:24:48.924+05:30Awesome n useful , but can improve by adding more ...Awesome n useful , but can improve by adding more infos Anonymoushttps://www.blogger.com/profile/10030045071195466526noreply@blogger.comtag:blogger.com,1999:blog-5895376483669856676.post-21419528624301068972016-07-16T22:53:01.578+05:302016-07-16T22:53:01.578+05:30LT^-1LT^-1Anonymoushttps://www.blogger.com/profile/07706300579877911426noreply@blogger.comtag:blogger.com,1999:blog-5895376483669856676.post-5478322219792027712016-07-16T22:50:53.588+05:302016-07-16T22:50:53.588+05:30Thank you but didn't understand 22^nd question...Thank you but didn't understand 22^nd question😅Anonymoushttps://www.blogger.com/profile/07706300579877911426noreply@blogger.comtag:blogger.com,1999:blog-5895376483669856676.post-12093818897260586962016-07-11T19:11:01.804+05:302016-07-11T19:11:01.804+05:30how can i download this..?how can i download this..?alizbluehttps://www.blogger.com/profile/09568480562379487113noreply@blogger.comtag:blogger.com,1999:blog-5895376483669856676.post-75721371793034331502016-06-19T13:30:59.964+05:302016-06-19T13:30:59.964+05:30but put different types of numericals modals
but put different types of numericals modals<br />Anonymoushttps://www.blogger.com/profile/15966807194509613512noreply@blogger.comtag:blogger.com,1999:blog-5895376483669856676.post-91903887187796768462016-06-18T08:15:25.992+05:302016-06-18T08:15:25.992+05:30please solve my problem:-
1.The position x of a pa...please solve my problem:-<br />1.The position x of a particle at time t is given by <br /> x=b/a(1-e^at) where a and b are non-zero constants.Find the dimension of b. Anonymoushttps://www.blogger.com/profile/08972177277054426642noreply@blogger.comtag:blogger.com,1999:blog-5895376483669856676.post-92171285075391419972016-06-02T19:09:26.777+05:302016-06-02T19:09:26.777+05:30Since trigonometric functions does not have dimens...Since trigonometric functions does not have dimensions,so sin(wt-kx) would be cancel out.therefore,y=L and a=L,so it is dimensionally correctAnonymoushttps://www.blogger.com/profile/02420864600435044607noreply@blogger.comtag:blogger.com,1999:blog-5895376483669856676.post-45539957298500132782015-12-26T09:58:21.030+05:302015-12-26T09:58:21.030+05:30Vry usful..question Vry usful..question ARJIT KUMAR SINGHhttps://www.blogger.com/profile/07506596776154546982noreply@blogger.comtag:blogger.com,1999:blog-5895376483669856676.post-80152257353071264812015-11-23T02:25:09.717+05:302015-11-23T02:25:09.717+05:30Someone please help..
To keep an object in a circl...Someone please help..<br />To keep an object in a circle at constant speed requires a force called the centripetal force. Do a dimensional analysis of the centripetal force.. Anonymoushttps://www.blogger.com/profile/02119263659982404961noreply@blogger.comtag:blogger.com,1999:blog-5895376483669856676.post-26207535150580499702015-09-08T21:58:57.088+05:302015-09-08T21:58:57.088+05:30will u plzz solve ... y=asin(wt-kx)
where,,
y=di...will u plzz solve ... y=asin(wt-kx) <br /> where,,<br />y=displacement<br />a=amplitude <br />t=time & <br />x=distanceAnonymoushttps://www.blogger.com/profile/15015488443538242695noreply@blogger.comtag:blogger.com,1999:blog-5895376483669856676.post-20176922081112677462015-08-20T14:23:56.971+05:302015-08-20T14:23:56.971+05:30why we not use degree symbol in kelvin temparature...why we not use degree symbol in kelvin temparature representation?<br />Anonymoushttps://www.blogger.com/profile/01088815355426482449noreply@blogger.comtag:blogger.com,1999:blog-5895376483669856676.post-90492825826204543532015-08-20T14:22:16.145+05:302015-08-20T14:22:16.145+05:30if force depends on masses m1, m2 and distance bet...if force depends on masses m1, m2 and distance between masses i.e. r than how do we find dimension formulae of force?<br />Anonymoushttps://www.blogger.com/profile/01088815355426482449noreply@blogger.comtag:blogger.com,1999:blog-5895376483669856676.post-45623042904397932242015-08-20T14:19:35.723+05:302015-08-20T14:19:35.723+05:30pls sugest method.
pls sugest method.<br />Anonymoushttps://www.blogger.com/profile/01088815355426482449noreply@blogger.comtag:blogger.com,1999:blog-5895376483669856676.post-33939360131751351932015-07-15T19:02:20.447+05:302015-07-15T19:02:20.447+05:30tqs once againtqs once againAnonymoushttps://www.blogger.com/profile/18246176317817711254noreply@blogger.comtag:blogger.com,1999:blog-5895376483669856676.post-65538111642705014042015-06-24T12:32:44.755+05:302015-06-24T12:32:44.755+05:30thnks very much to cbse .its vrry nicethnks very much to cbse .its vrry niceAnonymoushttps://www.blogger.com/profile/02879234101059024577noreply@blogger.com