CBSE Class 10 - March 2014 English (Comm) Question paper Format

CBSE Class 10 - English (Comm)- March 2014 - Modified Syllabus, Question Paper Design

CBSE Class 10 - Maths - CH 14 - Statistics (Ex 14.1)

Statistics

(NCERT Ex 14.1)

Q1: A survey was conducted by a group of students as a part of their environment awareness programme, in which they collected the following data regarding the number of plants in 20 houses in a locality. Find the mean number of plants per house.


Answer:

We use the following relation to find the class mark (x_i) for each interval:

Class mark (x_i) =

Calculating x_i and f_ix_i as follows:

Number of plants	Number of houses(fi)	xi	fixi
0 -2	1	1	1 ☓ 1 = 1
2 -4	2	3	2 ☓ 3 = 6
4 -6	1	5	1 ☓ 5 = 5
6 -8	5	7	5 ☓ 7 = 35
8 - 10	6	9	6 ☓ 9 = 54
10 -12	2	11	2 ☓ 11 = 22
12 - 14	3	13	3 ☓ 13 = 39
Total	20		162

From the table, it is observed that

Σ f_i = 20

Σ f_ix_i = 162

Mean , x =

= = 8.1

Therefore, mean number of plants per house is 8.1.

Here, direct method has been used as the values of class marks (x_i) and f_i are small.


Q2: Consider the following distribution of daily wages of 50 worker of a factory.

Daily wages(in Rs)	100 - 120	120 - 140	140 - 160	160 - 180	180 - 200
Number of workers	12	14	8	6	10

Find the mean daily wages of the workers of the factory by using an appropriate method.

Answer:

CBSE Class 10 - Political Science - CH6 Political Parties

Q & As

Q1: What is a political party?

Answer: A political party is a group of people who come together and participate in political campaigns, contest elections, form and run governments by holding power in the government.


Q2: What are the components of a political party?

Answer: A political party has following three components:

1. the leader
2. active members 
3. followers

Q3: State the various functions political parties perform in a democracy?

Answer: Main functions performed by a political party are:

1. It agrees collectively on various social policies and promote its programmes.
2. It seeks to implement these policies by winning public support through political campaigns.
3. It participates and contest elections.
4. It plays a decisive role in law making.
5. It plays a role of opposition and exercise check on the government (or ruling party).

CBSE Class 8 - Maths - CH 6 - Square and Square Roots (Ex 6.4)

Square and Square roots

Exercise 6.4

Q1: Find the square root of each of the following numbers by division method.

(i)2304  (ii) 4489  (iii)3481  (iv) 529   (v)3249 (vi) 1369

(vii)5776 (viii) 7921  (ix)576 (x) 1024 (xi)3136 (xii) 900

Answer:

(i)The square root of 2304 is calculated as follows.

	48
4	23 04 -16
88	704 704
	0

∴√ 2304  = 48

(ii)The square root of 4489 is calculated as follows.

	67
6	44 89 -36
127	889 889
	0

∴√ 4489  = 67

(iii)The square root of 3481 is calculated as follows.

	59
5	34 81 -25
109	981 981
	0

∴√ 3481  = 59

(iv)The square root of 529 is calculated as follows.

	23
5	5 29 -4
43	129 129
	0

∴√ 529  = 23

(v)The square root of 3249 is calculated as follows.

	57
5	32 49 -25
107	749 749
	0

∴√ 3249  = 57

(vi)The square root of 1369 is calculated as follows.

	37
3	13 69 -9
67	469 469
	0

∴√ 1369  = 37

(vii)The square root of 5776 is calculated as follows.

	76
7	57 76 -49
146	876 876
	0

∴√ 5776  = 76

CBSE Class 8 - Maths - Cube and Cube Roots (Ex 7.1)

Cube and Cube Roots 

(NCERT Ex 7.1)

Q1: Which of the following numbers are not perfect cubes?
(i)  216
(ii) 128
(iii) 1000
(iv) 100
(v) 46656

Answer:

(i) The prime factorisation of 216 is as follows:

2	216
2	108
2	54
3	27
3	9
3	3
	1

∴ 216 = 2 ☓ 2 ☓ 2 ☓ 3 ☓ 3 ☓ 3 = 2³ ☓ 3³

Here, each prime factor appears as many times as a perfect multiple of 3, therefore, 216 is a
perfect cube.

(ii) The prime factorisation of 128 is as follows:

2	128
2	64
2	32
2	16
2	8
2	4
2	2
	1

∴  128 = 2 ☓ 2 ☓ 2 ☓ 2 ☓ 2 ☓ 2 ☓ 2

Here, each prime factor does not appear as many times as a perfect multiple of 3. Therefore, 128 is not a perfect cube.

(iii)The prime factorisation of 1000 is as follows.

2	1000
2	500
2	250
5	125
5	25
5	5
	1

∴ 1000 = 2 ☓ 2 ☓ 2 ☓ 5 ☓ 5 ☓ 5 =  2³ ☓ 5³

Here, as each prime factor appears as many times as a perfect multiple of 3, therefore, 1000 is a perfect cube.

(iv)The prime factorisation of 100 is as follows.

2	100
2	50
5	25
5	5
	1

∴ 100 = 2 ☓ 2 ☓ 5 ☓ 5

Here, each prime factor does not form triplet group(s). Therefore, 100 is not a perfect cube.

(iv) The prime factorisation of 46656 is as follows.

2	46656
2	23328
2	11664
2	5832
2	2916
2	1458
3	729
3	243
3	81
3	27
3	9
3	3
	1

46656 = 2 ☓ 2 ☓ 2 ☓ 2 ☓ 2 ☓ 2 ☓ 3 ☓ 3 ☓ 3 ☓ 3 ☓ 3 ☓ 3
 = 2³ ☓ 2³ ☓ 3³ ☓ 3³
Here, each prime factor appears as many times as a perfect multiple of 3,
∴ 46656 is a perfect cube.

Q2: Find the smallest number by which each of the following numbers must be multiplied to obtain a perfect cube.

CBSE Class 6 - History - CH 11 - New Empires and Kingdoms

New Empires and Kingdoms

Coin showing Samudraguta with Garuda pillar
credits:wikimedia

(Q & A)

Q1: Name the famous rulers of Gupta dynasty?

Answer: Samudragupta and Chandragupta II (Vikramaditya)


Q2: What do you mean by Prashasti?

Answer:  Prashasti, a Sanskrit word, meaning ‘in praise of’. Generally, it is an inscription written in praise of  rulers. It also tells about the genealogy of the rulers.


Q3: Who composed Prashasti of Samudragupta and where it is inscribed at?

Answer: Harishena composed a long poem in praise of King Samudragupta. It is inscribed on Ashokan pillar at Allahabad.


Q4: What was the old name of Allahabad?

Answer: Prayag


Q5: Who was the founder of Gupta dynasty?

Answer: Chandragupta I


Q6: Write a short note on Chandragupta I

Answer:

1. Chandragupta I, the first ruler of Gupta dynasty, ascended throne of Magadha in 320 AD.
2. He married to Kumaradevi, a princess of Lichchavi tribe.
3. He expanded his kingdom upto Allahabad and took the title of Maharajadhiraj.

CBSE Class 7 - Science - CH 14 - Electric Current and Its Effects (MCQs)

Electric Current and its Effects
(MCQs)

Why CFL is better than electric bulb?

Q1: The unit to measure electric resistance is:
 
(a) Joule
(b) Ohm
(c) Ampere
(d) Volt


Q2: The device used to make or break an electric circuit is:

(a) Resistor
(b) Battery
(c) Switch
(d) Ammeter


 
Q3: When an electric current passes through a solenoid, it acts as a/an

(a) insulator
(b) electric bell
(c) resistor
(d) bar magnet


Q4:  Which of the following is an essential element in an electric circuit?