Wednesday, 28 November 2018

Class 10 - Chemistry - Carbon and Its Compounds (NCERT In Text Activities Solved) (#cbsenotes)(#eduvictors)

Class 10 - Chemistry

Carbon and Its Compounds 

(NCERT In Text Activities Solved)
Class 10 - Chemistry - Carbon and Its Compounds (NCERT In Text Activities Solved) (#cbsenotes)(#eduvictors)


Activity 4.1
● Make a list of ten things you have used or consumed since the morning.

● Compile this list with the lists made by your classmates and then sort the items into the adjacent Table.

● If there are items which are made up of more than one material, put them into both the relevant columns.

Answer:

(C) -> Indicates carbon-based material.





Items Things made of metal Things made of glass/clay Others
Spoon, Utensils Aluminium/Iron -
Fan Iron/Aluminium
Bed, Chair - - Wood (C)
Clothes - - Cellulose(C)
Toothbrush - - Plastic (C)
Tumbler - - -
Books - - Wood Pulp, Cellulose (C)
Pencils - - Plastic (C)
Car Iron Glass Plastic (C)
Pencil Wood (C), Graphite (C)
Mobile Phones Glass Plastic (C), Elctronic Chips(C)

Observations:
1. Most of the substances contain carbon in it.

Table 4.3

Class 10 - Chemistry - Carbon and Its Compounds (NCERT In Text Activities Solved) (#cbsenotes)(#eduvictors)

Activity 4.2
● Calculate the difference in the formulae and molecular masses for
(a) CH₃OH and C₂H₅OH
(b) C₂H₅OH and C₃H₇OH, and
(c) C₃H₇OH and C₄H₉OH.

● Is there any similarity in these three?

● Arrange these alcohols in the order of increasing carbon atoms to get a family. Can we call this family a homologous series?

● Generate the homologous series for compounds containing up to four carbons for the other functional groups given in Table 4.3.


Answer:
(a) CH₃OH and C₂H₅OH  differ by -CH₂
Mass of CH₃OH = 12 + 1 × 3 + 16 + 1 = 32u
Mass of C₂H₅OH = (12 × 2) + (1 × 5) + 16 + 1 = 46u
Difference → 46 – 32 = 14u

(b) C₂H₅OH and C₃H₇OH differ by -CH₂
Mass of C₂H₅OH = (12 × 2 ) + (1 × 5) + 16 + 1 = 46u
Mass of C₃H₇OH =  (12 × 3) + (1 × 7) + 16 + 1 = 60u
Difference → 60 – 46 = 14u

(c) C₃H₇OH and C₄H₉OH differ by -CH₂
Mass of C₃H₇OH = (12 × 3) + (1 × 7) + 16 + 1 = 60u
Mass of C₄H₉OH = 12 × 4) + (1 × 9) + 16 + 1 = 74u
Difference → 74 – 60 = 14u

All 3 groups given above show a similarity i.e. Two consecutive members differ by CH₂ group and mass 14u.


Class 10 - Chemistry - Carbon and Its Compounds (NCERT In Text Activities Solved) (#cbsenotes)(#eduvictors)

Activity 4.3
✐ CAUTION: This Activity needs the teacher’s assistance.

● Take some carbon compounds (naphthalene,camphor, alcohol) one by one on a spatula and burn
them.

● Observe the nature of the flame and note whether smoke is produced.

● Place a metal plate above the flame. Is there a deposition on the plate in case of any of the compounds?

Answer:
Heating of different carbon compounds, observing the flame and smoke.

Carbon Compounds Nature of flame Deposits on Metal
Camphor Smoky flame Carbon deposits on metal
Alcohol Non-sooty flame No carbon
Acetone Non-sooty flame No carbon
Naphthalene Smoky flame Carbon deposits on metal

Alcohol and acetone burns with non-sooty flame—complete combustion takes place.
Camphor, naphthalene burns with sooty flame—incomplete combustion takes place.