Wednesday, 28 November 2018

Class 10 - Chemistry - Carbon and Its Compounds (NCERT In Text Activities Solved) (#cbsenotes)(#eduvictors)

Class 10 - Chemistry

Carbon and Its Compounds 

(NCERT In Text Activities Solved)
Class 10 - Chemistry - Carbon and Its Compounds (NCERT In Text Activities Solved) (#cbsenotes)(#eduvictors)


Activity 4.1
Make a list of ten things you have used or consumed since the morning.

Compile this list with the lists made by your classmates and then sort the items into the adjacent Table.

If there are items which are made up of more than one material, put them into both the relevant columns.

Answer:

(C) -> Indicates carbon-based material.





Items Things made of metal Things made of glass/clay Others
Spoon, Utensils Aluminium/Iron -
Fan Iron/Aluminium
Bed, Chair - - Wood (C)
Clothes - - Cellulose(C)
Toothbrush - - Plastic (C)
Tumbler - - -
Books - - Wood Pulp, Cellulose (C)
Pencils - - Plastic (C)
Car Iron Glass Plastic (C)
Pencil Wood (C), Graphite (C)
Mobile Phones Glass Plastic (C), Elctronic Chips(C)

Observations:
1. Most of the substances contain carbon in it.

Table 4.3

Class 10 - Chemistry - Carbon and Its Compounds (NCERT In Text Activities Solved) (#cbsenotes)(#eduvictors)

Activity 4.2
Calculate the difference in the formulae and molecular masses for
(a) CH₃OH and C₂H₅OH
(b) C₂H₅OH and C₃H₇OH, and
(c) C₃H₇OH and C₄H₉OH.

Is there any similarity in these three?

Arrange these alcohols in the order of increasing carbon atoms to get a family. Can we call this family a homologous series?

Generate the homologous series for compounds containing up to four carbons for the other functional groups given in Table 4.3.


Answer:
(a) CH₃OH and C₂H₅OH  differ by -CH₂
Mass of CH₃OH = 12 + 1 × 3 + 16 + 1 = 32u
Mass of C₂H₅OH = (12 × 2) + (1 × 5) + 16 + 1 = 46u
Difference → 46 – 32 = 14u

(b) C₂H₅OH and C₃H₇OH differ by -CH₂
Mass of C₂H₅OH = (12 × 2 ) + (1 × 5) + 16 + 1 = 46u
Mass of C₃H₇OH =  (12 × 3) + (1 × 7) + 16 + 1 = 60u
Difference → 60 – 46 = 14u

(c) C₃H₇OH and C₄H₉OH differ by -CH₂
Mass of C₃H₇OH = (12 × 3) + (1 × 7) + 16 + 1 = 60u
Mass of C₄H₉OH = 12 × 4) + (1 × 9) + 16 + 1 = 74u
Difference → 74 – 60 = 14u

All 3 groups given above show a similarity i.e. Two consecutive members differ by CH₂ group and mass 14u.


Class 10 - Chemistry - Carbon and Its Compounds (NCERT In Text Activities Solved) (#cbsenotes)(#eduvictors)

Activity 4.3
CAUTION: This Activity needs the teacher’s assistance.

● Take some carbon compounds (naphthalene,camphor, alcohol) one by one on a spatula and burn
them.

● Observe the nature of the flame and note whether smoke is produced.

● Place a metal plate above the flame. Is there a deposition on the plate in case of any of the compounds?

Answer:
Heating of different carbon compounds, observing the flame and smoke.

Carbon Compounds Nature of flame Deposits on Metal
Camphor Smoky flame Carbon deposits on metal
Alcohol Non-sooty flame No carbon
Acetone Non-sooty flame No carbon
Naphthalene Smoky flame Carbon deposits on metal

Alcohol and acetone burns with non-sooty flame—complete combustion takes place.
Camphor, naphthalene burns with sooty flame—incomplete combustion takes place.