Floatation
7 Simple Numerical You Must Know
Answer:
Force = 200 N
Area = 10cm2 = 10 x 10-4m2
Pressure (P) = Force ÷ Area
P1 = 200 ÷ 10 x 10-4 = 2 x 105 Pa
New area = 50cm2 = 50 x 10-4m2
P2 = 200 ÷ 50 x 10-4 = 4 x 104 Pa
Change in Pressure = P1 - P2 = 2 x 105 - 4 x 104
= 1.6 x 105 Pa
Q2: A cuboid room has dimensions 50m x 15m x 3.5m. What is the mass of the air enclosed in the room if the density of air = 1.30 kg/m3.
Answer: Volume of room (V) = 50m x 15m x 3.5m = 2625m3
Density of air (d) = 1.30 kg/m3
Mass of air = V x d = 2625 x 1.30 = 3412.5 kg