CBSE Class 10 - Science - NTSE (Biology) Quiz - 18

NTSE Biology Quiz-18

Q1: We found heterotropic mode of nutrition in which of the following:
(a) Opuntia
(b) pistia
(c) Vallisneria
(d) Drosera


Q2: Which of the following is an example of insectivorous plant?
(a) Orobanche
(b) Rafflesia
(c) Cuscuta
(d) Drosera


Q3: Insectivorous plants
(a) are heterotropic
(b) can get supplementary protein food
(c) cannot manufacture their food other than carbohydrates
(d) cannot manufacture their own proteins

CBSE Class 9: Science Experiment (SA1) - Test the presence of adulterant metanil yellow in dal (MCQs)

Test the presence of adulterant metanil yellow in dal 

Metanil yellow is a synthetic dye which is not permitted to use as food colour. However it is used extensively in India to give yellow colour to Dal (pulses) and turmeric. Metanil yellow is toxic by nature and it has adverse effects on liver, intestine and brain.

To test the presence of metanil yellow in dal, take the following steps:

1. Take approximately 5 gms of dal in a test tube and add 5 ml of water. 
2. Shake the test tube well. 
3. Add few drops of concentrated hydrochloric acid to the test tube. (This activity should be done in the presence of your school teacher).
4. The appearance of a pink colour in the solution confirms the presence of metanil yellow in dal

(MCQs asked in CBSE examination)

Q1: Metanil yellow changes the colour of solution of dal to
(a) green
(b) pink
(c) blue
(d) dark red

CBSE Class 7 - Science - Ch1 - Nutrition in Plants (MCQs)

Nutrition in Plants

image credits: classroomclaipart

(MCQs)

Q1: Green plants are:
(a) herbivores
(b) autotrophs
(c) hetrotrophs
(d) omnivores

Q2: The tiny pores present in the leaves of the plants for exchange of gases are called _____

(a) Stomata
(b) Tracheae
(c) Chloroplast
(d) Spiracles


Q3: Rhizobium is an example of

(a) Symbiosis
(b) Parasites
(c) Insectivorous
(d) none of these

CBSE Class 6 - Science - Ch2: Components of Food (MCQs)

Components of Food 

(MCQs)

Q1: Which of the following is a protective food?
(a) milk
(b) oils & fats
(c) fruits
(d) cereals


Q2: Goitre: swelling of thyroid glands occurs due to the deficiency of _________.

(a) iron
(b) pottasium
(c) phosphorus
(d) iodine


Q3(NCERT): Which of the following nutrients is not present in milk?

(a) Protein
(b) Vitamin C
(c) Calcium
(d) Vitamin D

CBSE Class 6/7/8/9 - Hindi - अनौपचारिक पत्र

अनौपचारिक पत्र

१) मित्र को जन्मदिन के उपलक्ष्य में बधाई पत्र लिखो |

११२,शारदा निकेतन
दिल्ली |
दिनांक ----------

प्रिय मित्र -------,

सप्रेम नमस्कार |
कल ही मुझे तुम्हारे जन्मदिन का निमंत्रण पत्र मिला | मुझे यह जानकार अत्यंत प्रसन्नता हुई कि गत वर्ष की भाँति इस वर्ष भी तुम अपना जन्म-दिवस बड़ी धूमधाम से मना रही हो | इस शुभ अवसर पर सुबह अनाथालय जाकर बच्चों को खाना और कपड़े बाँटने का विचार अति उत्तम है | शाम को घर पर रखी पार्टी और उसमें आयोजित जादूगर का खेल अवश्य ही सबको पसंद आएगा | मेरी ओर से तुम्हें जन्मदिन की बहुत- बहुत बधाई | मैं तुम्हारे कार्यक्रम में अवश्य सम्मिलित होऊँगा/ होऊँगी |

पूज्य चाचा जी और चाची जी को मेरा प्रणाम कहना और सोनू को प्यार |

तुम्हारा मित्र/तुम्हारी सखी ,

क. ख. ग.


२) मित्र को परीक्षा में सफलता पर बधाई देते हुए पत्र लिखो |

CBSE Class 9 - Science Practical - Experiment: To study temporary mount of onion peel.

Experiment: To study Temporary Mount of Onion Peel

image credits:openclipart

MCQs

Q1: Which cells can we see while observing the slide of onion peel?

(a) Epithelial cells
(b) Epidermal cells
(c) Parenchymatous cells
(d) nerve cells


Q2: Which stain is used while observing onion cells?

(a) Safranin
(b) Iodine solution
(c) Methylene blue
(d) Alician blue


Q3: Shape of onion cells is

(a) square
(b) circular
(c) elliptical
(d) rectangular

Class 9 - Science - CH 8 - Motion (MCQs)

Motion

MCQs

Q1: A train moving with a uniform speed of 54 kmph. What is its speed in m/s?

(a) 15 m/s
(b) 1.5 m/s
(c) 9 m/s
(d) 90 m/s


Q2: A scalar quantity has ______________?

(a) magnitude only
(b) direction only
(c) both direction and magnitude
(d) none of these


Q3: When an object undergoes acceleration

(a) there is always an increase in its velocity
(b) there is always an increase in its speed
(c) a force always acting on it
(d) all of the above.

CBSE Class 6/7/8 - French Grammar - Les Verbes (Er-verbs)-2

Les Verbes

(Er-Verbs)

Er-verbs
☛ All verbs whose infinitive ends in ‘er’ belong to this group (except aller).
☛ The present tense of all –er  verbs is conjugated by removing the ‘er’ ending and adding the endings –e, -es, -e, -ons, -ez,-ent to the radical of the verb.

eg: Infinitive: parler---- Radical-parl ,     Infinitive-regarder---- Radical-regard

Parler-to speak

1st person	Singular	Je parle	I speak/I am speaking
2nd person	Singular	Tu parles	You speak/you are speaking
3rd person	Singular (m)	Il parle	He speaks/he is speaking
3rd person	Singular (f)	Elle parle	She speaks/she is speaking
1st person	Plural	Nous parlons	We speak/we are speaking
2nd person	Plural	Vous parlez	You speak/you are speaking
3rd person	Plural (m)	Ils parlent	They speak/they are speaking (m.p.)
3rd person	Plural (f)	Elles parlent	They speak/they are speaking (f.p.)

CBSE Class 6/7/8 - Hindi - औपचारिक पत्र

औपचारिक पत्र 

१)  अवकाश प्राप्ति हेतु प्रधानाचार्य जी को पत्र लिखें |

सेवा में
प्रधानाचार्य जी/प्रधानाचार्या जी
क.ख.ग. विद्यालय
महोदय/महोदया,

विषय - अवकाश प्राप्ति हेतु|

सविनय निवेदन है कि मैं आपके विद्यालय की कक्षा ---- की छात्रा/छात्र हूँ | कल विद्यालय से लौटते समय तेज़ बारिश में भीगने के कारण मुझे तेज़ ज्वर हो गया है | अतः मैं विद्यालय आने में असमर्थ हूँ | कृपया मुझे तीन दिन (दिनांक ११-४-१३ से १३-४-१३ ) का अवकाश प्रदान करें | आपकी अति कृपा होगी |

धन्यवाद|

आपकी आज्ञाकारी शिष्या/आपका आज्ञाकारी शिष्य,
कक्षा ------
अनुक्रमांक(roll no.)-----
दिनांक --------

CBSE Class 10 - Maths - Real Numbers (NCERT Ex 1.1)

Real Numbers

(NCERT Ex 1.1)

1. Use Euclid’s division algorithm to find the HCF of :
 
(i) 135 and 225 
(ii) 196 and 38220 
(iii) 867 and 255

Answer:
(i) 135 and 225
Step 1 : Since 225 > 135, apply Euclid’s division lemma to 225 and 135 to get
                                225 = 135 × 1 + 90

Step 2: Since remainder 90 ≠ 0, we apply the division lemma to 135 and 90 to get
                                135 = 90 × 1 + 45

Step 3: Now the remainder r = 45 ≠ 0 so we apply Euclid’s division lemma to 90 and 45 to have
                                 90 = 2 × 45 + 0

Step 4: The remainder has now become zero. Since the divisor at this stage is 45,
            ∴ HCF(135,225) =45

(ii) 196 and 38220
Step 1: Since 38220 > 196, apply the division lemma to 38220 and 196 to get
                            38220 = 196 × 195 + 0

Step 2: Since remainder is zero, the process stops. Since the divisor at this stage is 196,
             ∴ HCF(38220, 196) = 196

(iii) 867 and 255

Step 1: Since 867 > 255, we apply the division lemma to 867 and 255 to get
                   867 = 255 × 3 + 102
Step 2: Since remainder 102 ≠ 0, we apply the division lemma to 255 and 102 to have
                   255 = 102 × 2 + 51
Step 3: Now the new divisor  is 102 and new remainder is 51. Apply the division lemma to get
                   102 = 51 × 2 + 0
Step 4: Since the remainder is zero, the process stops. Since the divisor at this stage is 51,
              ∴ HCF(867, 255) = 51