Work, Energy and Power
Numerical Problems based on Class 9 Physics NCERT Chapter
Q1(CBSE 2012): State the relation between the commercial unit of energy and joules.
Answer: Kilowatt hour (kWh)
1 kwh - 3.6 x 106 joules
Q2: How much work is done on a body of mass 1kg whirling on a circular path of radius 5m?
Answer: Zero
Q3: A body of mass 15 kg undergoes downward displacement of 40m under the effect of gravitational force. How much work is done? (take g = 10 m/s2)
Answer:
Given
acceleration (a) = g = 10 m/s2
mass (m) = 15 kg
displacement (s) = 40 m
Work W = F × s
= m × a × s = 15 × 10 × 40 = 6000 J
Since gravitational force and displacement are in the same direction, work is said to be positive and done on the body.
Q4: A body of mass 120 g is taken vertically upwards to reach the height of 5m. Calculate work done. (Take g = 10 m/s2)
Answer: Given,
a = g = - 10 m/s2
m = 120g = 0.120 kg
s = 5m
Work W = F × s
= m × g × s = 0.12 × -10 × 5 = -6 J
a = g = - 10 m/s2
m = 120g = 0.120 kg
s = 5m
Work W = F × s
= m × g × s = 0.12 × -10 × 5 = -6 J
Since Force and displacement act in opposite directions, work is negative. Here work is considered to be done by the body against the applied force.
Q5: A momentum of the body is increased by 20%. What is the percentage increase in its kinetic energy?